Q. Use point-slope form to write the equation of a line that passes through the point (−1,−4) with slope 47.Answer:
Identify Point-Slope Form: Identify the point-slope form of a linear equation.The point-slope form of a linear equation is given by (y−y1)=m(x−x1), where m is the slope and (x1,y1) is a point on the line.
Plug Values: Plug the given point and slope into the point-slope form.Given point (x1,y1): (−1,−4)Given slope (m): 47Substitute these values into the point-slope form equation: (y−(−4))=(47)(x−(−1))
Simplify Equation: Simplify the equation.Simplify the equation by removing the parentheses and rewriting the equation as: y+4=(47)(x+1)
Distribute Slope: Distribute the slope to the terms inside the parentheses.Multiply 47 by each term inside the parentheses: y+4=(47)x+(47)(1)
Simplify Constant Term: Simplify the constant term.Multiply 47 by 1 to get 47: y+4=(47)x+47
Write Final Equation: Write the final equation in point-slope form.The final equation of the line in point-slope form is: y+4=(47)x+47
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