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Use point-slope form to write the equation of a line that passes through the point (-16,13) with slope -(3)/(5). Answer:

Use point-slope form to write the equation of a line that passes through the point (−16,13) (-16,13) with slope −35 -\frac{3}{5} .\newlineAnswer:

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Full solution

Q. Use point-slope form to write the equation of a line that passes through the point (−16,13) (-16,13) with slope −35 -\frac{3}{5} .\newlineAnswer:
  1. Identify Point and Slope: The point-slope form of a line is given by the equation y−y1=m(x−x1) y - y_1 = m(x - x_1) , where m m is the slope of the line and (x1,y1) (x_1, y_1) is a point on the line. We are given the point (−16,13) (-16, 13) and the slope m=−35 m = -\frac{3}{5} .
  2. Substitute into Point-Slope Form: Substitute the given point and slope into the point-slope form equation. This gives us y−13=−35(x−(−16)) y - 13 = -\frac{3}{5}(x - (-16)) .
  3. Distribute Slope: Simplify the equation by distributing the slope through the parentheses. This results in y−13=−35(x+16) y - 13 = -\frac{3}{5}(x + 16) .
  4. Final Equation: Further simplification is not necessary since the question asks for the equation in point-slope form. Therefore, the final equation is y−13=−35(x+16) y - 13 = -\frac{3}{5}(x + 16) .

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