Two airplanes leave the same airport. One heads north, and the other heads east. After some time, the northbound airplane has traveled 60 miles, and the eastbound airplane has traveled 80 miles. How far apart are the two airplanes?
Q. Two airplanes leave the same airport. One heads north, and the other heads east. After some time, the northbound airplane has traveled 60 miles, and the eastbound airplane has traveled 80 miles. How far apart are the two airplanes?
Identify Relationship: Identify the relationship between the distances traveled by the airplanes and the distance between them.The paths of the airplanes form a right-angled triangle, with the distances traveled as the legs and the distance between them as the hypotenuse.
Determine Leg Lengths: Determine the lengths of the legs of the triangle.Northbound airplane: 60 milesEastbound airplane: 80 milesThese are the legs of the right-angled triangle.
Apply Pythagorean Theorem: Apply the Pythagorean Theorem to find the distance between the airplanes.The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse c is equal to the sum of the squares of the lengths of the other two sides a and b.a2+b2=c2
Solve for Distance: Plug in the known values into the Pythagorean Theorem and solve for c. (60 miles)2+(80 miles)2=c23600+6400=c210000=c2
Find Square Root: Take the square root of both sides to find the value of c.10000=c2100=c
Conclude Final Answer: Conclude with the final answer.The distance between the two airplanes is 100 miles.
More problems from Pythagorean Theorem and its converse