Triangle BCD is dilated by a scale factor of (2)/(3) to form triangle B^(')C^(')D^('). Side B^(')C^(') measures 12 . What is the measure of side BC ? Answer:

Understand Relationship: Understand the relationship between the sides of the original triangle and the dilated triangle. When a triangle is dilated by a scale factor, all sides are multiplied by that scale factor. In this case, the scale factor is 2/3, which means each side of triangle BCD is 3/2 times the corresponding side of triangle B'C'D'.Calculate Side BC: Calculate the measure of side BC using the scale factor and the measure of side B'C'. Since B'C' is the dilated side and measures 12 units, we can find BC by dividing the length of B'C' by the scale factor of 2/3. BC = B'C' / (2/3)Perform Division: Perform the division to find the length of BC. BC = 12 / (2/3) BC = 12 * (3/2) BC = 18

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Triangle BCD is dilated by a scale factor of
(2)/(3) to form triangle
B^(')C^(')D^('). Side
B^(')C^(') measures 12 . What is the measure of side
BC ?
Answer:

Triangle BCD is dilated by a scale factor of $\frac{2}{3}$ to form triangle $B^{\prime} C^{\prime} D^{\prime}$ . Side $B^{\prime} C^{\prime}$ measures $12$ . What is the measure of side $\mathrm{BC}$ ? $\newline$ Answer:

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Q. Triangle BCD is dilated by a scale factor of

\frac{2}{3}

to form triangle

B^{\prime} C^{\prime} D^{\prime}

. Side

B^{\prime} C^{\prime}

measures

12

. What is the measure of side

\mathrm{BC}

\newline

Answer:

Understand Relationship: Understand the relationship between the sides of the original triangle and the dilated triangle. $\newline$ When a triangle is dilated by a scale factor, all sides are multiplied by that scale factor. In this case, the scale factor is $\frac{2}{3}$ , which means each side of triangle $BCD$ is $\frac{3}{2}$ times the corresponding side of triangle $B'C'D'$ .
Calculate Side BC: Calculate the measure of side $BC$ using the scale factor and the measure of side $B'C'$ . Since $B'C'$ is the dilated side and measures $12$ units, we can find $BC$ by dividing the length of $B'C'$ by the scale factor of $\frac{2}{3}$ . $BC = \frac{B'C'}{\frac{2}{3}}$
Perform Division: Perform the division to find the length of $BC$ . $BC = \frac{12}{\left(\frac{2}{3}\right)}$ $BC = 12 \times \left(\frac{3}{2}\right)$ $BC = 18$