Q. Three points on the graph of the function f(x) are {(0,1),(1,4),(2,9)}. Which equation represents f(x) ?f(x)=5x−1f(x)=4xf(x)=(x+1)2f(x)=3x+1
Test Equation f(x): Test the first equation f(x)=5x−1 with the given points.Substitute x=0 into f(x)=5x−1 to see if it gives y=1.f(0)=5(0)−1=−1Check if this matches the given point (0,1).
Check f(x)=5x−1: Since f(0)=−1 does not match the given point (0,1), we can conclude that f(x)=5x−1 is not the correct equation.
Test Equation f(x): Test the second equation f(x)=4x with the given points.Substitute x=0 into f(x)=4x to see if it gives y=1.f(0)=40=1Check if this matches the given point (0,1).
Check f(x)=4x: Since f(0)=1 matches the given point (0,1), we proceed to test the next point (1,4). Substitute x=1 into f(x)=4x to see if it gives y=4. f(1)=41=4 Check if this matches the given point (1,4).
Test Equation f(x): Since f(1)=4 matches the given point (1,4), we proceed to test the last point (2,9).Substitute x=2 into f(x)=4x to see if it gives y=9.f(2)=42=16Check if this matches the given point (2,9).
Check f(x)=(x+1)2: Since f(2)=16 does not match the given point (2,9), we can conclude that f(x)=4x is not the correct equation.
Check f(x)=(x+1)2: Since f(2)=16 does not match the given point (2,9), we can conclude that f(x)=4x is not the correct equation.Test the third equation f(x)=(x+1)2 with the given points.Substitute x=0 into f(x)=(x+1)2 to see if it gives y=1.f(0)=(0+1)2=1Check if this matches the given point (0,1).
Check f(x)=(x+1)2: Since f(2)=16 does not match the given point (2,9), we can conclude that f(x)=4x is not the correct equation.Test the third equation f(x)=(x+1)2 with the given points.Substitute x=0 into f(x)=(x+1)2 to see if it gives y=1.f(0)=(0+1)2=1Check if this matches the given point (0,1).Since f(2)=160 matches the given point (0,1), we proceed to test the next point f(2)=162.Substitute f(2)=163 into f(x)=(x+1)2 to see if it gives f(2)=165.f(2)=166Check if this matches the given point f(2)=162.
Check f(x)=(x+1)2: Since f(2)=16 does not match the given point (2,9), we can conclude that f(x)=4x is not the correct equation.Test the third equation f(x)=(x+1)2 with the given points.Substitute x=0 into f(x)=(x+1)2 to see if it gives y=1.f(0)=(0+1)2=1Check if this matches the given point (0,1).Since f(2)=160 matches the given point (0,1), we proceed to test the next point f(2)=162.Substitute f(2)=163 into f(x)=(x+1)2 to see if it gives f(2)=165.f(2)=166Check if this matches the given point f(2)=162.Since f(2)=168 matches the given point f(2)=162, we proceed to test the last point (2,9).Substitute (2,9)1 into f(x)=(x+1)2 to see if it gives (2,9)3.(2,9)4Check if this matches the given point (2,9).
Check f(x)=(x+1)2: Since f(2)=16 does not match the given point (2,9), we can conclude that f(x)=4x is not the correct equation.Test the third equation f(x)=(x+1)2 with the given points.Substitute x=0 into f(x)=(x+1)2 to see if it gives y=1.f(0)=(0+1)2=1Check if this matches the given point (0,1).Since f(2)=160 matches the given point (0,1), we proceed to test the next point f(2)=162.Substitute f(2)=163 into f(x)=(x+1)2 to see if it gives f(2)=165.f(2)=166Check if this matches the given point f(2)=162.Since f(2)=168 matches the given point f(2)=162, we proceed to test the last point (2,9).Substitute (2,9)1 into f(x)=(x+1)2 to see if it gives (2,9)3.(2,9)4Check if this matches the given point (2,9).Since (2,9)6 matches the given point (2,9), we can conclude that f(x)=(x+1)2 is the correct equation that represents (2,9)9.
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