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The YMCA lap pool is a right rectangular prism 
36.8m long by 
20m wide. The pool contains 
1472m^(3) of water.
How deep is the water in the pool?
m

The YMCA lap pool is a right rectangular prism 36.8 m 36.8 \mathrm{~m} long by 20 m 20 \mathrm{~m} wide. The pool contains 1472 m3 1472 \mathrm{~m}^{3} of water.\newlineHow deep is the water in the pool?\newlinem

Full solution

Q. The YMCA lap pool is a right rectangular prism 36.8 m 36.8 \mathrm{~m} long by 20 m 20 \mathrm{~m} wide. The pool contains 1472 m3 1472 \mathrm{~m}^{3} of water.\newlineHow deep is the water in the pool?\newlinem
  1. Identify formula: Identify the formula to calculate the volume of a right rectangular prism.\newlineThe volume VV of a right rectangular prism can be calculated by multiplying its length LL, width WW, and height HH.\newlineV=L×W×HV = L \times W \times H
  2. Given values: Given values for the problem.\newlineThe length LL of the pool is 36.836.8 meters, the width WW is 2020 meters, and the volume VV of water is 14721472 cubic meters.\newlineL=36.8mL = 36.8\,\text{m}, W=20mW = 20\,\text{m}, V=1472m3V = 1472\,\text{m}^3
  3. Solve for height: Solve for the height HH, which represents the depth of the water in the pool.\newlineUsing the formula V=L×W×HV = L \times W \times H, we can rearrange it to solve for HH:\newlineH=VL×WH = \frac{V}{L \times W}
  4. Substitute and calculate: Substitute the given values into the formula and calculate the depth of the water.\newlineH=1472m3(36.8m×20m)H = \frac{1472m^3}{(36.8m \times 20m)}\newlineH=1472m3736m2H = \frac{1472m^3}{736m^2}\newlineH=2mH = 2m

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