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Let’s check out your problem:
The sum of two numbers is
17
17
17
. One number is
3
3
3
less than
2
3
\frac{2}{3}
3
2
of the other number. What is the lesser number?
\newline
12
12
12
\newline
7
7
7
\newline
5
5
5
\newline
3
3
3
\newline
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Math Problems
Grade 7
Round mixed numbers
Full solution
Q.
The sum of two numbers is
17
17
17
. One number is
3
3
3
less than
2
3
\frac{2}{3}
3
2
of the other number. What is the lesser number?
\newline
12
12
12
\newline
7
7
7
\newline
5
5
5
\newline
3
3
3
\newline
Define Variables:
Let
x
x
x
be the larger number and
y
y
y
be the smaller number. The sum of the two numbers is given as
17
17
17
. So, we write the equation:
\newline
x
+
y
=
17
x + y = 17
x
+
y
=
17
Express Relationship:
It's also given that one number is
3
3
3
less than two-thirds of the other number. We can express this relationship as:
y
=
2
3
x
−
3
y = \frac{2}{3}x - 3
y
=
3
2
x
−
3
Substitute and Simplify:
Substitute the expression for
y
y
y
from the second equation into the first equation:
\newline
x
+
2
3
x
−
3
=
17
x + \frac{2}{3}x - 3 = 17
x
+
3
2
x
−
3
=
17
Combine Like Terms:
Combine like terms:
5
3
x
−
3
=
17
\frac{5}{3}x - 3 = 17
3
5
x
−
3
=
17
Isolate
x
x
x
:
Solve for
x
x
x
by first adding
3
3
3
to both sides:
\newline
(
5
3
)
x
=
20
(\frac{5}{3})x = 20
(
3
5
)
x
=
20
Find
y
y
y
:
Multiply both sides by
3
5
\frac{3}{5}
5
3
to isolate
x
x
x
:
x
=
(
3
5
)
×
20
x = \left(\frac{3}{5}\right) \times 20
x
=
(
5
3
)
×
20
x
=
12
x = 12
x
=
12
Final Solution:
Substitute
x
=
12
x = 12
x
=
12
back into the equation for
y
y
y
:
y
=
(
2
3
)
∗
12
−
3
y = \left(\frac{2}{3}\right)*12 - 3
y
=
(
3
2
)
∗
12
−
3
y
=
8
−
3
y = 8 - 3
y
=
8
−
3
y
=
5
y = 5
y
=
5
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\newline
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\underline{\hspace{1em}}
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\underline{\hspace{1em}}
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\newline
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\newline
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