The sum of the digits of a two digit number is 8 and the difference between the number and that formed by reversing the digits is 18. Find the number.−533553−35
Q. The sum of the digits of a two digit number is 8 and the difference between the number and that formed by reversing the digits is 18. Find the number.−533553−35
Identify Digits: Let's denote the tens digit of the number as x and the units digit as y. The two-digit number can be represented as 10x+y. The number formed by reversing its digits is 10y+x. According to the problem, the sum of the digits is 8, which gives us the equation:x+y=8
Form Equations: The difference between the original number and the reversed number is 18, which gives us the second equation:(10x+y)−(10y+x)=18Simplifying this, we get:9x−9y=18Dividing both sides by 9, we get:x−y=2
Solve System: Now we have a system of two linear equations:1) x+y=82) x−y=2We can solve this system by adding the two equations together to eliminate y.(1)+(2) gives us:x+y+x−y=8+22x=10Dividing both sides by 2, we get:x=5
Find Tens Digit: Now that we have the value of x, we can substitute it back into one of the original equations to find y. Let's use the first equation:x+y=85+y=8Subtracting 5 from both sides, we get:y=8−5y=3
Substitute and Calculate: We have found that x (the tens digit) is 5 and y (the units digit) is 3. Therefore, the original two-digit number is: 10x+y=10×5+3=50+3=53
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