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The sum of an integer and 7 times the next consecutive even integer is 94 . Find the value of the lesser integer.
Answer:

The sum of an integer and 77 times the next consecutive even integer is 9494 . Find the value of the lesser integer.\newlineAnswer:

Full solution

Q. The sum of an integer and 77 times the next consecutive even integer is 9494 . Find the value of the lesser integer.\newlineAnswer:
  1. Identify Integers: Let's denote the lesser integer as xx. Since we are looking for consecutive even integers, the next consecutive even integer would be x+2x + 2. The problem states that the sum of the lesser integer and 77 times the next consecutive even integer is 9494. We can write this as an equation:\newlinex+7(x+2)=94x + 7(x + 2) = 94
  2. Write Equation: Now, let's distribute the 77 into the parentheses: x+7x+14=94x + 7x + 14 = 94
  3. Distribute and Simplify: Combine like terms to simplify the equation: 8x+14=948x + 14 = 94
  4. Isolate Variable: Subtract 1414 from both sides to isolate the term with the variable:\newline8x=94148x = 94 - 14\newline8x=808x = 80
  5. Solve for x: Divide both sides by 88 to solve for x:\newlinex=808x = \frac{80}{8}\newlinex=10x = 10
  6. Check Solution: We have found the value of the lesser integer, which is 1010. To ensure that we have not made any mistakes, let's check our solution by plugging it back into the original equation:\newline10+7(10+2)=9410 + 7(10 + 2) = 94\newline10+7(12)=9410 + 7(12) = 94\newline10+84=9410 + 84 = 94\newline94=9494 = 94\newlineThe solution checks out.

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