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The rate of change 
(dP)/(dt) of the number of people on an island is modeled by a logistic differential equation. The maximum capacity of the island is 926 people. At 
11AM, the number of people on the island is 135 and is increasing at a rate of 28 people per hour. Write a differential equation to describe the situation.

(dP)/(dt)=◻" Submit Answer "

The rate of change dPdt \frac{d P}{d t} of the number of people on an island is modeled by a logistic differential equation. The maximum capacity of the island is 926926 people. At 11AM 11 \mathrm{AM} , the number of people on the island is 135135 and is increasing at a rate of 2828 people per hour. Write a differential equation to describe the situation.\newlinedPdt= Submit Answer  \frac{d P}{d t}=\square \text { Submit Answer }

Full solution

Q. The rate of change dPdt \frac{d P}{d t} of the number of people on an island is modeled by a logistic differential equation. The maximum capacity of the island is 926926 people. At 11AM 11 \mathrm{AM} , the number of people on the island is 135135 and is increasing at a rate of 2828 people per hour. Write a differential equation to describe the situation.\newlinedPdt= Submit Answer  \frac{d P}{d t}=\square \text { Submit Answer }
  1. Logistic Differential Equation: The logistic differential equation is generally given by the formula:\newlinedPdt=rP(1PK) \frac{dP}{dt} = rP\left(1 - \frac{P}{K}\right) \newlinewhere P P is the population at time t t , r r is the intrinsic growth rate, and K K is the carrying capacity of the environment. In this case, K K is given as 926926 people.
  2. Given Population and Rate: We are given that at 1111AM, the number of people on the island is 135135, which is P P at t=11AM t = 11AM , and the rate of increase dPdt \frac{dP}{dt} is 2828 people per hour. However, we need to find the intrinsic growth rate r r to complete the differential equation.
  3. Calculate Intrinsic Growth Rate: To find the intrinsic growth rate r r , we can use the given rate of increase when P=135 P = 135 . Plugging these values into the logistic equation, we get:\newline28=r135(1135926) 28 = r \cdot 135\left(1 - \frac{135}{926}\right) \newlineNow we need to solve for r r .
  4. Calculate Fraction of Carrying Capacity: First, calculate the fraction of the carrying capacity:\newline1135926=10.145790.85421 1 - \frac{135}{926} = 1 - 0.14579 \approx 0.85421
  5. Calculate Term: Now, multiply this fraction by 135135 to find the term 135(1135926) 135\left(1 - \frac{135}{926}\right) :\newline1350.85421115.3185 135 \cdot 0.85421 \approx 115.3185
  6. Calculate Intrinsic Growth Rate: Next, divide the rate of increase by this term to find r r :\newliner=28115.31850.2428 per hour r = \frac{28}{115.3185} \approx 0.2428 \text{ per hour}
  7. Complete Differential Equation: Now that we have r r , we can write the complete logistic differential equation:\newlinedPdt=0.2428P(1P926) \frac{dP}{dt} = 0.2428P\left(1 - \frac{P}{926}\right) \newlineThis is the differential equation that describes the situation.

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