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The rate of change 
(dP)/(dt) of the number of people entering a movie theatre is modeled by a logistic differential equation. The maximum capacity of the theatre is 775 people. At 
12AM, the number of people at the movie theatre is 246 and is increasing at a rate of 36 people per hour. Write a differential equation to describe the situation.

(dP)/(dt)=◻" Submit Answer "

The rate of change dPdt \frac{d P}{d t} of the number of people entering a movie theatre is modeled by a logistic differential equation. The maximum capacity of the theatre is 775775 people. At 12AM 12 \mathrm{AM} , the number of people at the movie theatre is 246246 and is increasing at a rate of 3636 people per hour. Write a differential equation to describe the situation.\newlinedPdt= Submit Answer  \frac{d P}{d t}=\square \text { Submit Answer }

Full solution

Q. The rate of change dPdt \frac{d P}{d t} of the number of people entering a movie theatre is modeled by a logistic differential equation. The maximum capacity of the theatre is 775775 people. At 12AM 12 \mathrm{AM} , the number of people at the movie theatre is 246246 and is increasing at a rate of 3636 people per hour. Write a differential equation to describe the situation.\newlinedPdt= Submit Answer  \frac{d P}{d t}=\square \text { Submit Answer }
  1. Logistic Differential Equation: The logistic differential equation is generally given by the formula:\newlinedPdt=rP(1PK) \frac{dP}{dt} = rP\left(1 - \frac{P}{K}\right) \newlinewhere P P is the population at time t t , r r is the intrinsic growth rate, and K K is the carrying capacity, which in this case is the maximum capacity of the theatre.
  2. Maximum Capacity of Theatre: We are given that the maximum capacity K K of the theatre is 775775 people. This is the carrying capacity in our logistic model.
  3. Initial Condition: We are also given that at 1212 AM, the number of people P P is 246246 and is increasing at a rate of 3636 people per hour. This gives us the initial condition for P P and the rate of change dPdt \frac{dP}{dt} at that specific time.
  4. Finding Intrinsic Growth Rate: To find the intrinsic growth rate r r , we use the given rate of change when P=246 P = 246 . Plugging these values into the logistic equation, we get:\newline36=r246(1246775) 36 = r \cdot 246 \left(1 - \frac{246}{775}\right) \newlineNow we solve for r r .
  5. Calculating Fraction: First, calculate the fraction of the carrying capacity:\newline1246775=10.3174=0.6826 1 - \frac{246}{775} = 1 - 0.3174 = 0.6826
  6. Solving for r: Now, solve for r r :\newline36=r2460.6826 36 = r \cdot 246 \cdot 0.6826 \newliner=362460.682636167.79960.2145 per hour r = \frac{36}{246 \cdot 0.6826} \approx \frac{36}{167.7996} \approx 0.2145 \text{ per hour}
  7. Complete Logistic Differential Equation: Now that we have the value for r r , we can write the complete logistic differential equation:\newlinedPdt=0.2145P(1P775) \frac{dP}{dt} = 0.2145P\left(1 - \frac{P}{775}\right) \newlineThis is the differential equation that describes the situation.

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