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The points (9,g)(9,g) and (8,−3)(8,-3) fall on a line with a slope of 1010. What is the value of gg?\newlineg=___g = \_\_\_

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Q. The points (9,g)(9,g) and (8,−3)(8,-3) fall on a line with a slope of 1010. What is the value of gg?\newlineg=___g = \_\_\_
  1. Identify Points and Slope: Identify the given points and the slope.\newlineWe have the points (9,g)(9, g) and (8,−3)(8, -3) and the slope of the line is 1010.\newlineWe will use the slope formula which is (y2−y1)/(x2−x1)=slope.(y_2 - y_1) / (x_2 - x_1) = \text{slope}.
  2. Plug Values into Formula: Plug the values into the slope formula.\newlineUsing the points (9,g)(9, g) as (x2,y2)(x_2, y_2) and (8,−3)(8, -3) as (x1,y1)(x_1, y_1), we get:\newline10=g−(−3)9−810 = \frac{g - (-3)}{9 - 8}
  3. Simplify Equation: Simplify the equation. 10=(g+3)110 = \frac{(g + 3)}{1}
  4. Isolate Variable: Multiply both sides by 11 to isolate gg. \newline10×1=(g+3)10 \times 1 = (g + 3)\newline10=g+310 = g + 3
  5. Solve for gg: Solve for gg.\newlineSubtract 33 from both sides to find the value of gg.\newline10−3=g10 - 3 = g\newline7=g7 = g

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