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The points (8,8)(8,8) and (−6,a)(-6,a) fall on a line with a slope of 11. What is the value of aa?\newlinea=a = ____

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Full solution

Q. The points (8,8)(8,8) and (−6,a)(-6,a) fall on a line with a slope of 11. What is the value of aa?\newlinea=a = ____
  1. Calculate slope formula: Calculate the slope using the formula (y2−y1)/(x2−x1)(y_2 - y_1) / (x_2 - x_1) where (x1,y1)=(8,8)(x_1, y_1) = (8, 8) and (x2,y2)=(−6,a)(x_2, y_2) = (-6, a).\newlineSlope = (a−8)/(−6−8)(a - 8) / (-6 - 8)\newline1=(a−8)/−141 = (a - 8) / -14
  2. Solve for a: Solve for a by cross-multiplying.\newline1×−14=a−81 \times -14 = a - 8\newline−14=a−8-14 = a - 8
  3. Isolate aa: Isolate aa by adding 88 to both sides.\newline−14+8=a-14 + 8 = a\newline−6=a-6 = a

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