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The points (7,8)(-7,-8) and (6,h)(-6,h) fall on a line with a slope of 22. What is the value of hh?\newlineh=h = ____

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Q. The points (7,8)(-7,-8) and (6,h)(-6,h) fall on a line with a slope of 22. What is the value of hh?\newlineh=h = ____
  1. Identify formula for slope: Identify the formula for slope between two points.\newlineThe slope formula is (y2y1)/(x2x1)(y_2 - y_1) / (x_2 - x_1). Here, (x1,y1)=(7,8)(x_1, y_1) = (-7, -8) and (x2,y2)=(6,h)(x_2, y_2) = (-6, h).
  2. Plug in values and slope: Plug in the values and the given slope into the slope formula.\newlineSlope = 22, so:\newline2=h(8)6(7)2 = \frac{h - (-8)}{-6 - (-7)}\newline2=h+86+72 = \frac{h + 8}{-6 + 7}
  3. Simplify denominator and solve: Simplify the denominator and solve for hh.2=h+812 = \frac{h + 8}{1}2×1=h+82 \times 1 = h + 82=h+82 = h + 8

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