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The points (−6,k)(-6,k) and (−7,−2)(-7,-2) fall on a line with a slope of 88. What is the value of kk?\newlinek=___k = \_\_\_

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Q. The points (−6,k)(-6,k) and (−7,−2)(-7,-2) fall on a line with a slope of 88. What is the value of kk?\newlinek=___k = \_\_\_
  1. Calculate Slope: Points: (−6,k)(-6, k) and (−7,−2)(-7, -2); Slope: 88. Using the slope formula: Slope = y2−y1x2−x1\frac{y_2 - y_1}{x_2 - x_1}. 8=k−(−2)−6−(−7)8 = \frac{k - (-2)}{-6 - (-7)}.
  2. Simplify Equation: Simplify the equation:\newline8=k+2−6+78 = \frac{k + 2}{-6 + 7}.\newline8=k+2−18 = \frac{k + 2}{-1}.
  3. Isolate kk: Multiply both sides by −1-1 to isolate k+2k + 2:8×−1=(k+2)−1×−1.8 \times -1 = \frac{(k + 2)}{-1} \times -1.−8=k+2.-8 = k + 2.
  4. Solve for k: Solve for k:\newline−8−2=k.-8 - 2 = k.\newlinek=−10.k = -10.

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