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The points (−5,7)(-5,7) and (−6,g)(-6,g) fall on a line with a slope of 1010. What is the value of gg?\newlineg=___g = \_\_\_

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Q. The points (−5,7)(-5,7) and (−6,g)(-6,g) fall on a line with a slope of 1010. What is the value of gg?\newlineg=___g = \_\_\_
  1. Identify Points and Slope: Identify the given points and slope.\newlinePoints: (−5,7)(-5, 7) and (−6,g)(-6, g)\newlineSlope: 1010\newlineUse the slope formula: Slope=y2−y1x2−x1\text{Slope} = \frac{y_2 - y_1}{x_2 - x_1}\newline10=g−7−6+510 = \frac{g - 7}{-6 + 5}
  2. Use Slope Formula: Simplify the equation.\newline10=g−7−110 = \frac{g - 7}{-1}\newlineMultiply both sides by −1-1 to isolate g−7g - 7.\newline10×−1=g−7−1×−110 \times -1 = \frac{g - 7}{-1} \times -1\newline−10=g−7-10 = g - 7
  3. Simplify Equation: Solve for gg.−10=g−7-10 = g - 7Add 77 to both sides.−10+7=g-10 + 7 = g−3=g-3 = g

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