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The points (−5,3)(-5,3) and (−4,p)(-4,p) fall on a line with a slope of −9-9. What is the value of pp?\newlinep=___p = \_\_\_

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Q. The points (−5,3)(-5,3) and (−4,p)(-4,p) fall on a line with a slope of −9-9. What is the value of pp?\newlinep=___p = \_\_\_
  1. Identify Given Points and Slope: Step 11: Identify the given points and slope.\newlinePoints: (−5,3)(-5, 3) and (−4,p)(-4, p)\newlineSlope: −9-9\newlineUse the slope formula: Slope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}\newline−9=p−3−4+5-9 = \frac{p - 3}{-4 + 5}
  2. Simplify the Equation: Step 22: Simplify the equation.\newline−9=p−31-9 = \frac{p - 3}{1}\newline−9=p−3-9 = p - 3
  3. Solve for p: Step 33: Solve for p.\newline−9+3=p-9 + 3 = p\newlinep=−6p = -6

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