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The points (3,10)(3,10) and (2,c)(2,c) fall on a line with a slope of 66. What is the value of cc?\newlinec = ____

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Q. The points (3,10)(3,10) and (2,c)(2,c) fall on a line with a slope of 66. What is the value of cc?\newlinec = ____
  1. Identify Given Points and Slope: Identify the given points and the slope.\newlineWe have the points (3,10)(3,10) and (2,c)(2,c) and the slope of the line is 66.\newlineWe will use the slope formula which is (y2y1)/(x2x1)=slope.(y_2 - y_1) / (x_2 - x_1) = \text{slope}.
  2. Plug Values into Formula: Plug the values into the slope formula.\newlineUsing the points (3,10)(3,10) and (2,c)(2,c), we get:\newline6=c10236 = \frac{c - 10}{2 - 3}
  3. Simplify Denominator: Simplify the denominator.\newlineSince 232 - 3 equals 1-1, we can rewrite the equation as:\newline6=(c10)16 = \frac{(c - 10)}{-1}
  4. Multiply to Isolate Term: Multiply both sides by 1-1 to isolate the term with cc.6×1=c101×16 \times -1 = \frac{c - 10}{-1} \times -16=c10-6 = c - 10
  5. Solve for c: Solve for c by adding 1010 to both sides of the equation.\newline6+10=c10+10-6 + 10 = c - 10 + 10\newline4=c4 = c

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