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The points (−3,1)(-3,1) and (1,k)(1,k) fall on a line with a slope of 11. What is the value of kk?\newlinek=___k = \_\_\_

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Full solution

Q. The points (−3,1)(-3,1) and (1,k)(1,k) fall on a line with a slope of 11. What is the value of kk?\newlinek=___k = \_\_\_
  1. Calculate slope formula: Calculate the slope using the formula for slope between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2): y2−y1x2−x1\frac{y_2 - y_1}{x_2 - x_1}. Here, x1=−3x_1 = -3, y1=1y_1 = 1, x2=1x_2 = 1, and y2=ky_2 = k.
  2. Simplify denominator and solve: Simplify the denominator and solve for kk.
  3. Isolate k−1k - 1: Multiply both sides by 44 to isolate k−1k - 1.
  4. Add 11 to solve for kk: Add 11 to both sides to solve for kk.

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