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The points (−2,n)(-2,n) and (−1,−5)(-1,-5) fall on a line with a slope of −4-4. What is the value of nn?\newlinen=___n = \_\_\_

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Q. The points (−2,n)(-2,n) and (−1,−5)(-1,-5) fall on a line with a slope of −4-4. What is the value of nn?\newlinen=___n = \_\_\_
  1. Identify Given Points and Slope: Identify the given points and slope.\newlinePoints: (−2,n)(-2, n) and (−1,−5)(-1, -5); Slope =−4= -4.\newlineUse the slope formula: Slope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}.\newline−4=−5−n−1+2.-4 = \frac{-5 - n}{-1 + 2}.
  2. Use Slope Formula: Simplify the equation.\newline−4=−5−n1-4 = \frac{-5 - n}{1}.\newlineMultiply both sides by 11 to isolate the terms involving nn.\newline−4=−5−n-4 = -5 - n.
  3. Simplify Equation: Solve for nn.−4+5=−n-4 + 5 = -n.1=−n1 = -n.n=−1n = -1.

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