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The points (2,k)(2,k) and (3,10)(3,10) fall on a line with a slope of 77. What is the value of kk?\newlinek = ____

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Q. The points (2,k)(2,k) and (3,10)(3,10) fall on a line with a slope of 77. What is the value of kk?\newlinek = ____
  1. Set up equation using slope formula: Points: (2,k)(2, k) and (3,10)(3, 10)\newlineSlope: 77\newlineUse the slope formula to set up the equation.\newlineSlope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}\newline7=10−k3−27 = \frac{10 - k}{3 - 2}
  2. Simplify the equation: 7=(10−k)(3−2)7 = \frac{(10 - k)}{(3 - 2)}\newlineSimplify the denominator.\newline7=(10−k)17 = \frac{(10 - k)}{1}\newline7=10−k7 = 10 - k
  3. Solve for k: 7=10−k7 = 10 - k Solve for k. 7+k=107 + k = 10 k=10−7k = 10 - 7 k=3k = 3

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