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The points (10,f)(10,f) and (9,8)(9,8) fall on a line with a slope of −6-6. What is the value of ff?\newlinef = ____

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Full solution

Q. The points (10,f)(10,f) and (9,8)(9,8) fall on a line with a slope of −6-6. What is the value of ff?\newlinef = ____
  1. Identify Points and Slope: Identify the given points and slope.\newlineWe have the points (10,f)(10, f) and (9,8)(9, 8), and the slope of the line is −6-6.
  2. Use Slope Formula: Use the slope formula to set up an equation.\newlineThe slope formula is (y2−y1)/(x2−x1)(y_2 - y_1) / (x_2 - x_1). Let's plug in our values:\newline−6=(8−f)/(9−10)-6 = (8 - f) / (9 - 10)
  3. Simplify Denominator: Simplify the denominator of the slope equation.\newline−6=8−f−1-6 = \frac{8 - f}{-1}
  4. Isolate Term with ff: Multiply both sides by −1-1 to isolate the term with ff.\newline−6×(−1)=8−f−1×(−1)-6 \times (-1) = \frac{8 - f}{-1} \times (-1)\newline6=8−f6 = 8 - f
  5. Solve for ff: Solve for ff by moving the terms around.\newline6=8−f6 = 8 - f\newline6−8=−f6 - 8 = -f\newline−2=−f-2 = -f\newlinef=2f = 2

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