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The points (−10,c)(-10,c) and (−9,−10)(-9,-10) fall on a line with a slope of −2-2. What is the value of cc?\newlinec=___c = \_\_\_

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Q. The points (−10,c)(-10,c) and (−9,−10)(-9,-10) fall on a line with a slope of −2-2. What is the value of cc?\newlinec=___c = \_\_\_
  1. Calculate Slope: Points: (−10,c)(-10, c) and (−9,−10)(-9, -10). Slope: −2-2.\newlineUse the slope formula: Slope=(y2−y1)(x2−x1)\text{Slope} = \frac{(y_2 - y_1)}{(x_2 - x_1)}.\newline−2=(−10−c)(−9+10)-2 = \frac{(-10 - c)}{(-9 + 10)}
  2. Simplify Equation: Simplify the denominator and solve for cc.−2=−10−c1-2 = \frac{-10 - c}{1}−2=−10−c-2 = -10 - c
  3. Isolate Variable: Add 1010 to both sides to isolate cc.
    −2+10=−10−c+10-2 + 10 = -10 - c + 10
    8=−c8 = -c
  4. Solve for c: Multiply both sides by −1-1 to solve for c.\newline8×−1=−c×−18 \times -1 = -c \times -1\newline−8=c-8 = c

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