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The points (1,w)(1,w) and (3,3)(3,-3) fall on a line with a slope of 6-6. What is the value of ww?\newlinew = ____

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Q. The points (1,w)(1,w) and (3,3)(3,-3) fall on a line with a slope of 6-6. What is the value of ww?\newlinew = ____
  1. Slope Formula: We know the slope formula for a line passing through two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by:\newlineslope mm = y2y1x2x1\frac{y_2 - y_1}{x_2 - x_1}\newlineWe are given the slope of the line 6-6, one point (3,3)(3, -3), and the x-coordinate of the other point (1)(1). We need to find the y-coordinate of the other point, which is ww.
  2. Plug in Values: Let's plug in the values we have into the slope formula:\newline6=w(3)13-6 = \frac{w - (-3)}{1 - 3}
  3. Simplify Equation: Simplify the equation:\newline6=w+313-6 = \frac{w + 3}{1 - 3}\newline6=w+32-6 = \frac{w + 3}{-2}
  4. Multiply by 2-2: To find ww, we need to solve for it by multiplying both sides of the equation by 2-2:\newline6×2=(w+3)-6 \times -2 = (w + 3)
  5. Subtract 33: Perform the multiplication: 12=w+312 = w + 3
  6. Find Value of w: Now, subtract 33 from both sides to isolate ww: 123=w12 - 3 = w
  7. Find Value of w: Now, subtract 33 from both sides to isolate ww: \newline123=w12 - 3 = w Perform the subtraction to find the value of ww: \newline9=w9 = w

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