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The points (−1,10)(-1,10) and (0,c)(0,c) fall on a line with a slope of −10-10. What is the value of cc?\newlinec = ____

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Full solution

Q. The points (−1,10)(-1,10) and (0,c)(0,c) fall on a line with a slope of −10-10. What is the value of cc?\newlinec = ____
  1. Given Points and Slope: We are given two points on a line: (−1,10)(-1,10) and (0,c)(0,c). We are also given the slope of the line, which is −10-10. The slope formula is (y2−y1)/(x2−x1)(y_2 - y_1) / (x_2 - x_1). We can use this formula to find the value of cc.
  2. Plug in Values: Let's plug in the values into the slope formula. We have:\newlineSlope mm = (c−10)/(0−(−1))(c - 10) / (0 - (-1))\newline−10-10 = (c−10)/1(c - 10) / 1\newlineNow we can solve for cc.
  3. Solve for c: Multiply both sides of the equation by 11 to isolate the term with cc:−10×1=c−10-10 \times 1 = c - 10This simplifies to:−10=c−10-10 = c - 10
  4. Isolate c: Now, add 1010 to both sides of the equation to solve for cc: \newline−10+10=c−10+10-10 + 10 = c - 10 + 10\newlineThis simplifies to:\newline0=c0 = c

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