The parabola y=x^2 is scaled vertically by a factor of 1/10 . What is the equation of the new parabola?

Multiply output by 1/10: To scale the parabola y = x^2 vertically by a factor of 1/10, we multiply the output (y-value) by 1/10.Update equation: The original equation is y = x^2. After scaling, the new equation becomes y = (1/10)x^2.Check for correct scaling: Check the new equation to ensure that the scaling factor has been applied correctly. The original parabola y = x^2, when scaled by 1/10, should result in the y-values being 1/10th of the original y-values. For example, if x = 2, the original y-value is 2^2 = 4. The new y-value should be 1/10 of 4, which is 0.4. Substituting x = 2 into the new equation gives y = (1/10)(2^2) = (1/10)(4) = 0.4, which is correct.

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The parabola $y=x^2$ is scaled vertically by a factor of $\frac{1}{10}$ . What is the equation of the new parabola?

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Q. The parabola

y=x^2

is scaled vertically by a factor of

\frac{1}{10}

. What is the equation of the new parabola?

Multiply output by $\frac{1}{10}$ : To scale the parabola $y = x^2$ vertically by a factor of $\frac{1}{10}$ , we multiply the output (y-value) by $\frac{1}{10}$ .
Update equation: The original equation is $y = x^2$ . After scaling, the new equation becomes $y = \frac{1}{10}x^2$ .
Check for correct scaling: Check the new equation to ensure that the scaling factor has been applied correctly. The original parabola $y = x^2$ , when scaled by $\frac{1}{10}$ , should result in the $y$ -values being $\frac{1}{10}$ th of the original $y$ -values. For example, if $x = 2$ , the original $y$ -value is $2^2 = 4$ . The new $y$ -value should be $\frac{1}{10}$ of $\frac{1}{10}$ $0$ , which is $\frac{1}{10}$ $1$ . Substituting $x = 2$ into the new equation gives $\frac{1}{10}$ $3$ , which is correct.