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The Olympic-size pool at the recreational center is a right rectangular prism 
50m long and 
25m wide. The pool contains 
3000m^(3) of water.
How deep is the water in the pool?
m

The Olympic-size pool at the recreational center is a right rectangular prism 50 m 50 \mathrm{~m} long and 25 m 25 \mathrm{~m} wide. The pool contains 3000 m3 3000 \mathrm{~m}^{3} of water.\newlineHow deep is the water in the pool?\newlinem

Full solution

Q. The Olympic-size pool at the recreational center is a right rectangular prism 50 m 50 \mathrm{~m} long and 25 m 25 \mathrm{~m} wide. The pool contains 3000 m3 3000 \mathrm{~m}^{3} of water.\newlineHow deep is the water in the pool?\newlinem
  1. Identify Volume Formula: To find the depth of the pool, we need to use the volume formula for a rectangular prism, which is Volume=Length×Width×Height\text{Volume} = \text{Length} \times \text{Width} \times \text{Height}. We know the volume, length, and width, so we can solve for the height, which represents the depth of the water in the pool.
  2. List Known Values: First, let's write down the known values:\newlineVolume VV = 30003000\newlineLength LL = 5050 m\newlineWidth WW = 2525 m\newlineWe need to find the Height HH, which is the depth of the water.
  3. Apply Volume Formula: Using the formula for the volume of a rectangular prism, we have:\newlineV=L×W×HV = L \times W \times H\newlinePlugging in the known values, we get:\newline3000m3=50m×25m×H3000 \, \text{m}^3 = 50 \, \text{m} \times 25 \, \text{m} \times H
  4. Calculate Height: To find the depth HH, we need to divide the volume by the product of the length and width:\newlineH=VL×WH = \frac{V}{L \times W}\newlineH=3000m350m×25mH = \frac{3000 \, \text{m}^3}{50 \, \text{m} \times 25 \, \text{m}}
  5. Final Depth Calculation: Now, we perform the calculation:\newlineH=3000m31250m2H = \frac{3000 \, \text{m}^3}{1250 \, \text{m}^2}\newlineH=2.4mH = 2.4 \, \text{m}\newlineSo, the depth of the water in the pool is 2.42.4 meters.

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