The number of girls in Stephen's class exceeded the number of boys by 8 . If there were 36 pupils in the class, how many were girls and how many were boys?

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Equation 1: Let's denote the number of boys as B and the number of girls as G. According to the problem, the number of girls exceeded the number of boys by 8, so we can write the following equation: G = B + 8Equation 2: We also know that the total number of pupils in the class is 36. This gives us a second equation: G + B = 36Substitute and Solve: Now we have a system of two equations with two variables: 1) G = B + 8 2) G + B = 36 We can substitute the expression for G from the first equation into the second equation to find the value of B. (B + 8) + B = 36Find Boys: Solving for B, we combine like terms: 2B + 8 = 36 2B = 36 - 8 2B = 28 B = 28 / 2 B = 14 So, there are 14 boys in the class.Find Girls: Now that we know the number of boys, we can find the number of girls using the first equation: G = B + 8 G = 14 + 8 G = 22 So, there are 22 girls in the class.

The number of girls in Stephen's class exceeded the number of boys by $8$ . If there were $36$ pupils in the class, how many were girls and how many were boys?

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The number of girls in Stephen's class exceeded the number of boys by $8$ . If there were $36$ pupils in the class, how many were girls and how many were boys?