The kinetic energy, measured in kilogram meters squared per second squared ((kg*m^(2))/(s^(2))), of the International Space Station is approximately: 13,340,250,000,000(kg*m^(2))/(s^(2)) If 1 Joule (J) is equal to 1(kg*m^(2))/(s^(2)) , and 1 terajoule (TJ) is equal to 10^(12)J, what is the approximate kinetic energy of the Space Station in terajoules to the nearest hundredth? Choose 1 answer: (A) 0.1334TJ (B) 1.334TJ (C) 13.34TJ (D) 13.34*10^(12)TJ

Understand conversion factors: Understand the conversion factors. 1 Joule (J) is equal to 1 (kg*m^(2))/(s^(2)). 1 terajoule (TJ) is equal to 10^(12) J.Convert to Joules: Convert the given kinetic energy in (kg*m^(2))/(s^(2)) to Joules. The given kinetic energy is 13,340,250,000,000 (kg*m^(2))/(s^(2)). Since 1 (kg*m^(2))/(s^(2)) is equal to 1 J, the kinetic energy in Joules is also 13,340,250,000,000 J.Convert to terajoules: Convert the kinetic energy from Joules to terajoules. To convert from Joules to terajoules, divide the energy in Joules by 10^(12). 13,340,250,000,000 J / 10^(12) = 13.34025 TJ.Round the result: Round the result to the nearest hundredth. Rounding 13.34025 to the nearest hundredth gives us 13.34 TJ.

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The kinetic energy, measured in kilogram meters squared per second squared
((kg*m^(2))/(s^(2))), of the International Space Station is approximately:

13,340,250,000,000(kg*m^(2))/(s^(2))
If 1 Joule
(J) is equal to
1(kg*m^(2))/(s^(2)) , and 1 terajoule
(TJ) is equal to
10^(12)J, what is the approximate kinetic energy of the Space Station in terajoules to the nearest hundredth?
Choose 1 answer:
(A)
0.1334TJ
(B)
1.334TJ
(C)
13.34TJ
(D)
13.34*10^(12)TJ

The kinetic energy, measured in kilogram meters squared per second squared $\left(\frac{\text{kg} \cdot \text{m}^2}{\text{s}^2}\right)$ , of the International Space Station is approximately: $\newline$ $13,340,250,000,000 \frac{\text{kg} \cdot \text{m}^2}{\text{s}^2}$ $\newline$ If $1$ Joule $J$ is equal to $1 \frac{\text{kg} \cdot \text{m}^2}{\text{s}^2}$ , and $1$ terajoule $TJ$ is equal to $10^{12}J$ , what is the approximate kinetic energy of the Space Station in terajoules to the nearest hundredth? $\newline$ Choose $1$ answer: $\newline$ (A) $0.1334\,TJ$ $\newline$ (B) $1.334\,TJ$ $\newline$ (C) $13.34\,TJ$ $\newline$ (D) $13.34 \times 10^{12}\,TJ$

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Q. The kinetic energy, measured in kilogram meters squared per second squared

\left(\frac{\text{kg} \cdot \text{m}^2}{\text{s}^2}\right)

, of the International Space Station is approximately:

\newline

13,340,250,000,000 \frac{\text{kg} \cdot \text{m}^2}{\text{s}^2}

\newline

1

Joule

J

is equal to

1 \frac{\text{kg} \cdot \text{m}^2}{\text{s}^2}

, and

1

terajoule

TJ

is equal to

10^{12}J

, what is the approximate kinetic energy of the Space Station in terajoules to the nearest hundredth?

\newline

Choose

1

answer:

\newline

(A)

0.1334\,TJ

\newline

(B)

1.334\,TJ

\newline

(C)

13.34\,TJ

\newline

(D)

13.34 \times 10^{12}\,TJ

Understand conversion factors: Understand the conversion factors. $\newline$ $1$ Joule (J) is equal to $1 \, (\text{kg} \cdot \text{m}^{2})/(\text{s}^{2})$ . $\newline$ $1$ terajoule (TJ) is equal to $10^{12} \, \text{J}$ .
Convert to Joules: Convert the given kinetic energy in $(\text{kg}\cdot\text{m}^{2})/(\text{s}^{2})$ to Joules. $\newline$ The given kinetic energy is $13,340,250,000,000$ $(\text{kg}\cdot\text{m}^{2})/(\text{s}^{2})$ . $\newline$ Since $1$ $(\text{kg}\cdot\text{m}^{2})/(\text{s}^{2})$ is equal to $1$ J, the kinetic energy in Joules is also $13,340,250,000,000$ J.
Convert to terajoules: Convert the kinetic energy from Joules to terajoules. $\newline$ To convert from Joules to terajoules, divide the energy in Joules by $10^{12}$ . $\newline$ $13,340,250,000,000 \, \text{J} / 10^{12} = 13.34025 \, \text{TJ}.$
Round the result: Round the result to the nearest hundredth. $\newline$ Rounding $13.34025$ to the nearest hundredth gives us $13.34$ TJ.