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The graph of function 
h follows. Let 
f(x)=int_(-1)^(x)h(t)dt.
Evaluate 
f(4).

f(4)=

The graph of function h h follows. Let f(x)=1xh(t)dt f(x)=\int_{-1}^{x} h(t) d t .\newlineEvaluate f(4) f(4) .\newlinef(4)= f(4)=

Full solution

Q. The graph of function h h follows. Let f(x)=1xh(t)dt f(x)=\int_{-1}^{x} h(t) d t .\newlineEvaluate f(4) f(4) .\newlinef(4)= f(4)=
  1. Substitute xx with 44: Substitute xx with 44 in the function f(x)f(x).f(4)=14h(t)dtf(4) = \int_{-1}^{4} h(t) \, dt
  2. Graph of h(t)h(t): Look at the graph of h(t)h(t) to find the area under the curve from 1-1 to 44. The graph shows a triangle from 1-1 to 00 and a rectangle from 00 to 44.
  3. Calculate triangle area: Calculate the area of the triangle.\newlineArea of triangle = 12×base×height\frac{1}{2} \times \text{base} \times \text{height}\newlineBase = 11 (from 1-1 to 00), height = 22 (from the x-axis to the peak of the triangle)\newlineArea\_triangle = 12×1×2=1\frac{1}{2} \times 1 \times 2 = 1
  4. Calculate rectangle area: Calculate the area of the rectangle.\newlineArea of rectangle = length×width\text{length} \times \text{width}\newlineLength = 44 (from 00 to 44), width = 22 (from the xx-axis to the top of the rectangle)\newlineArea\_rectangle = 4×2=84 \times 2 = 8
  5. Find total area: Add the areas of the triangle and rectangle to find the total area under the curve.\newlineTotal area = Areatriangle+Arearectangle\text{Area}_{\text{triangle}} + \text{Area}_{\text{rectangle}}\newlineTotal area = 1+8=91 + 8 = 9
  6. Total area under the curve: The total area under the curve from 1-1 to 44 is the value of f(4)f(4). \newlinef(4)=9f(4) = 9

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