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Let’s check out your problem:
The graph of function
f
f
f
is shown below. Let
g
(
x
)
=
∫
−
3
x
f
(
t
)
d
t
g(x)=\int_{-3}^{x} f(t) d t
g
(
x
)
=
∫
−
3
x
f
(
t
)
d
t
.
\newline
Evaluate
g
(
−
1
)
g(-1)
g
(
−
1
)
.
\newline
g
(
−
1
)
=
g(-1)=
g
(
−
1
)
=
View step-by-step help
Home
Math Problems
Algebra 2
Evaluate rational expressions II
Full solution
Q.
The graph of function
f
f
f
is shown below. Let
g
(
x
)
=
∫
−
3
x
f
(
t
)
d
t
g(x)=\int_{-3}^{x} f(t) d t
g
(
x
)
=
∫
−
3
x
f
(
t
)
d
t
.
\newline
Evaluate
g
(
−
1
)
g(-1)
g
(
−
1
)
.
\newline
g
(
−
1
)
=
g(-1)=
g
(
−
1
)
=
Identify Integral:
Identify the integral to evaluate:
g
(
−
1
)
=
∫
−
3
−
1
f
(
t
)
d
t
g(-1) = \int_{-3}^{-1} f(t) \, dt
g
(
−
1
)
=
∫
−
3
−
1
f
(
t
)
d
t
.
Graph Analysis:
Look at the graph of
f
(
t
)
f(t)
f
(
t
)
to determine the area under the curve from
−
3
-3
−
3
to
−
1
-1
−
1
.
Calculate Area:
Calculate the area of the shapes under the curve from
−
3
-3
−
3
to
−
1
-1
−
1
. If the graph is not provided, this step cannot be completed.
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Divide. Write the quotient in lowest terms.
\newline
1
7
9
÷
4
5
=
1 \frac{7}{9} \div \frac{4}{5}=
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Divide. Write the quotient in lowest terms.
\newline
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Divide. Write the quotient in lowest terms.
\newline
4
4
5
÷
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÷
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2
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Question
Divide. Write the quotient in lowest terms.
\newline
2
1
2
÷
2
2
3
=
2 \frac{1}{2} \div 2 \frac{2}{3}=
2
2
1
÷
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3
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Question
Divide. Write the quotient in lowest terms.
\newline
3
3
8
÷
9
=
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3
8
3
÷
9
=
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Question
Divide. Write the quotient in lowest terms.
\newline
3
3
10
÷
1
4
7
=
3 \frac{3}{10} \div 1 \frac{4}{7}=
3
10
3
÷
1
7
4
=
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Question
Divide. Write the quotient in lowest terms.
\newline
4
2
3
÷
7
=
4 \frac{2}{3} \div 7=
4
3
2
÷
7
=
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Posted 10 months ago
Question
d
d
x
[
8
x
2
+
2
x
−
3
]
=
?
\frac{d}{d x}\left[\sqrt{8 x^{2}+2 x-3}\right]=?
d
x
d
[
8
x
2
+
2
x
−
3
]
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
8
x
+
1
8
x
2
+
2
x
−
3
\frac{8 x+1}{\sqrt{8 x^{2}+2 x-3}}
8
x
2
+
2
x
−
3
8
x
+
1
\newline
(B)
8
x
+
1
x
\frac{8 x+1}{\sqrt{x}}
x
8
x
+
1
\newline
(c)
16
x
+
2
\sqrt{16 x+2}
16
x
+
2
\newline
(D)
1
2
16
x
+
2
\frac{1}{2 \sqrt{16 x+2}}
2
16
x
+
2
1
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Posted 9 months ago
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