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The given equation aimesx2+98x+ca imes x^2 + 98x + c has at least 11 real root and a factor of kx+jkx + j. What is the greatest possible value of acac?

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Q. The given equation aimesx2+98x+ca imes x^2 + 98x + c has at least 11 real root and a factor of kx+jkx + j. What is the greatest possible value of acac?
  1. Discriminant Calculation: Since the equation has at least one real root, the discriminant must be non-negative.\newlineDiscriminant: b24ac0b^2 - 4ac \geq 0\newlineHere, b=98b = 98, so:\newline9824ac098^2 - 4ac \geq 0
  2. Calculate 9898^22: Calculate 98298^2:\newline982=960498^2 = 9604\newlineSo:\newline96044ac09604 - 4ac \geq 0
  3. Solve for ac: Rearrange to solve for acac:\newline96044ac9604 \geq 4ac\newlineDivide both sides by 44:\newline2401ac2401 \geq ac
  4. Factorize Polynomial: Since kx+jkx + j is a factor, the polynomial can be written as:\newlinea(xr)(xs)a(x - r)(x - s)\newlineExpanding:\newlinea(x2(r+s)x+rs)a(x^2 - (r+s)x + rs)\newlineComparing with ax2+98x+ca \cdot x^2 + 98x + c:\newlinea(r+s)=98-a(r+s) = 98 and ars=cars = c
  5. Maximize ac: To maximize acac, we need to maximize rsrs while keeping a(r+s)=98-a(r+s) = 98.\newlineLet r=sr = s for simplicity:\newline2ar=98-2ar = 98\newlineSo:\newlinear=49ar = -49
  6. Substitute ar: Substitute ar=49ar = -49 into ars=cars = c:\newlinea(49)r=ca(-49)r = c\newlineSo:\newlinec=49rc = -49r
  7. Final Calculation: Now, ac=a(49r)ac = a \cdot (-49r):\newlineac=49arac = -49ar\newlineSince ar=49ar = -49:\newlineac=49(49)ac = -49(-49)\newlineac=2401ac = 2401

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