The fractionp of the population who has heard a breaking news story increases at a rate proportional to the fraction of the population who has not yet heard the news story.Which equation describes this relationship?Choose 1 answer:(A) dtdp=kp(B) dtdp=1−kp(C) dtdp=k(1−p)(D) dtdp=−kp
Q. The fraction p of the population who has heard a breaking news story increases at a rate proportional to the fraction of the population who has not yet heard the news story.Which equation describes this relationship?Choose 1 answer:(A) dtdp=kp(B) dtdp=1−kp(C) dtdp=k(1−p)(D) dtdp=−kp
Define p and rate: Let's denote p as the fraction of the population that has heard the news story at a given time t. The rate at which people hear the news story is given by dtdp, which is the derivative of p with respect to time t. Since the rate is proportional to the fraction of the population that has not yet heard the news story, we can express this as dtdp=k×(1−p), where k is the constant of proportionality. This is because 1−p represents the fraction of the population that has not heard the news story.
Check given options: Now let's check the given options to see which one matches our expression:(A) (dp)/(dt)=kp does not match because it suggests the rate is proportional to the fraction that has heard the news, not the fraction that hasn't.(B) (dp)/(dt)=1−kp does not match because it suggests the rate is equal to 1 minus the product of k and p, which does not represent a proportional relationship.(C) (dp)/(dt)=k(1−p) matches our derived expression and represents the rate being proportional to the fraction that has not heard the news.(D) (dp)/(dt)=−kp does not match because it suggests the rate is proportional to the fraction that has heard the news and is decreasing, which is not the case described.
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