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The first three terms of a sequence are given. Write your answer as a decimal or whole number. Round to the nearest thousandth (if necessary).

6,10,(50)/(3),dots
Find the 9th term.
Answer:

The first three terms of a sequence are given. Write your answer as a decimal or whole number. Round to the nearest thousandth (if necessary).\newline6,10,503, 6,10, \frac{50}{3}, \ldots \newlineFind the 99th term.\newlineAnswer:

Full solution

Q. The first three terms of a sequence are given. Write your answer as a decimal or whole number. Round to the nearest thousandth (if necessary).\newline6,10,503, 6,10, \frac{50}{3}, \ldots \newlineFind the 99th term.\newlineAnswer:
  1. Identify Pattern: Identify the pattern in the sequence.\newlineThe given sequence is 6,10,503,6, 10, \frac{50}{3}, \ldots To find the pattern, we need to look at the differences or ratios between the terms. Let's check the differences first.\newlineDifference between second and first term: 106=410 - 6 = 4\newlineDifference between third and second term: (503)10=(5030)/3=203(\frac{50}{3}) - 10 = (50 - 30)/3 = \frac{20}{3}\newlineThe differences are not constant, so this is not an arithmetic sequence. Let's check if it's a geometric sequence by finding the ratios.\newlineRatio of second to first term: 106=53\frac{10}{6} = \frac{5}{3}\newlineRatio of third to second term: (503)/10=(503)(110)=53(\frac{50}{3}) / 10 = (\frac{50}{3}) \cdot (\frac{1}{10}) = \frac{5}{3}\newlineThe ratios are constant, so this is a geometric sequence with a common ratio of 53\frac{5}{3}.
  2. Use Formula for 99th Term: Use the formula for the nth term of a geometric sequence to find the 99th term.\newlineThe formula for the nth term of a geometric sequence is an=a1×r(n1)a_n = a_1 \times r^{(n-1)}, where a1a_1 is the first term, rr is the common ratio, and nn is the term number.\newlineHere, a1=6a_1 = 6 (the first term), r=53r = \frac{5}{3} (the common ratio), and n=9n = 9 (since we're looking for the 99th term).\newlineLet's plug these values into the formula:\newlinea9=6×(53)91a_9 = 6 \times \left(\frac{5}{3}\right)^{9-1}\newline$a_9 = \(6\) \times \left(\frac{\(5\)}{\(3\)}\right)^\(8\)
  3. Calculate \(9\)th Term: Calculate the \(9\)th term. \(\newline\)\(a_9 = 6 \times \left(\frac{5}{3}\right)^8\)\(\newline\)To simplify this, we can calculate \(\left(\frac{5}{3}\right)^8\) first and then multiply by \(6\).\(\newline\)\(\left(\frac{5}{3}\right)^8 = \frac{5^8}{3^8}\)\(\newline\)\(= \frac{390625}{6561}\)\(\newline\)Now, multiply this by \(6\):\(\newline\)\(a_9 = 6 \times \left(\frac{390625}{6561}\right)\)\(\newline\)\(a_9 = \frac{2343750}{6561}\)
  4. Simplify Fraction: Simplify the fraction to get the decimal value. \(\newline\)\(a_9 = \frac{2343750}{6561}\)\(\newline\)To get the decimal value, we divide \(2343750\) by \(6561\).\(\newline\)\(a_9 \approx 357.210\)\(\newline\)Since we need to round to the nearest thousandth, the \(9\)th term is approximately \(357.210\).

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