Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The expression $4i$ gives the perimeter of a square with a side length of $i$ units.

View step-by-step help

View step-by-step help

Write equations of circles in standard form using properties

Full solution

Q. The expression

4i

gives the perimeter of a square with a side length of

i

units.

Identify side length: Identify the side length of the square from the given perimeter. $\newline$ Perimeter of a square = $4 \times \text{side length}$ . $\newline$ Given perimeter = $4i$ . $\newline$ So, side length = $i$ units.
Calculate area: Calculate the area of the square using the side length. $\newline$ Area = $\text{side length}^2$ . $\newline$ Area = $i^2$ .
Simplify expression: Simplify the expression for the area. $\newline$ $i^2 = -1$ (since $i$ is the imaginary unit and $i^2 = -1$ ). $\newline$ Area = $-1$ square units.

More problems from Write equations of circles in standard form using properties

Question

Write the equation of this line in slope-intercept form.

Posted 3 months ago

Question

You pick a card at random, put it back, and then pick another card at random.

\newline

4

\newline

5

\newline

6

\newline

7

\newline

What is the probability of picking a number greater than

5

and then picking a

4

\newline

Write your answer as a percentage.

Posted 1 month ago

Question

Jeanne's bank account earns interest annually. The equation shows her starting balance of

\$500

and her balance at the end of three years,

\$546.36

r

did Jeanne earn interest?

\newline

546.36 = 500(1 + r)

Posted 1 month ago

Question

Jeanne's bank account earns interest annually. The equation shows her starting balance of

\$ 350

and her balance at the end of three years,

\$ 422.78

. At what rate r did Jeanne earn interest?

\newline

422.78=350(1+r)^{3}

Posted 1 month ago

Question

10\text{-kg}

bucket is lifted from the ground to a height of

14\, \text{m}

at a constant speed with a rope that weighs

0.6\, \text{kg/m}

. Initially the bucket contains

42\, \text{kg}

of water, but the water leaks at a constant rate and finishes draining just as the bucket reaches the

14\, \text{m}

level. How much work is done? (Use

9.8\, \text{m/s}^2

g

.) Show how to approximate the required work (in

\text{J}

) by a Riemann sum. (Let

x

be the height in meters above the ground. Enter

x_i^*

x_i

Posted 1 month ago

Question

10-\mathrm{kg}

bucket is lifted from the ground to a height of

14

m at a constant speed with a rope that weighs

0.6 \mathrm{~kg} / \mathrm{m}

. Initially the bucket contains

42

kg of water, but the water leaks at a constant rate and finishes draining just as the bucket reaches the

14-\mathrm{m}

level. How much work is done? (Use

9.8 \mathrm{~m} / \mathrm{s}^{2}

\newline

Show how to approximate the required work (in J) by a Riemann sum. (Let

x

be the height in meters above the ground. Enter

x_{i}^{* *}

x_{i}

\newline

\lim _{n \rightarrow \infty} \sum_{i=1}^{n}\left(\boxed{98+35.28 x_{i}}\right) \Delta x

\newline

Express the work (in J) as an integral in terms of

x

\newline

\int_{0}^{14}(98+35.28 x

\newline

Evaluate the integral (in J). (Round your answer to the nearest integer.)

Posted 1 month ago

Question

Solve the equation.

\newline

6 w^{7}=98,304

Posted 1 month ago

Question

10\text{-kg}

bucket is lifted from the ground to a height of

14\text{ m}

at a constant speed with a rope that weighs

0.6\text{ kg/m}

. Initially the bucket contains

42\text{ kg}

of water, but the water leaks at a constant rate and finishes draining just as the bucket reaches the

14\text{-m}

level. How much work is done? (Use

9.8\text{ m/s}^2

g

.) Show how to approximate the required work (in

\text{J}

) by a Riemann sum. (Let

x

be the height in meters above the ground. Enter

x_i^*

x_i

Posted 1 month ago

Question

\begin{array}{l}f(t)=\left\{\begin{array}{ll}-\frac{64}{t} & , \quad t=8 \\ 14-t & , \quad t=10 \\ t^{2}-3 t+2 & , \quad t \neq 8,10\end{array}\right. \\ f(2)=\square\end{array}

Posted 1 month ago

Question

\begin{array}{l}f(x)=\left\{\begin{array}{lll}\frac{x-6}{3} & , \quad x=-18 \\\frac{360}{x} & , \quad x=36 \\4 x+73 & , \quad x \neq-18,36\end{array}\right. \\f(-18)=\end{array}

Posted 1 month ago

Related topics

Algebra - Order of Operations Algebra - Distributive Property `X` and `Y` Axes Geometry - Scalene Triangle Common Multiple Geometry - Quadrant