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The equation 
-x-2y=0 is graphed in the 
xy-plane. Which of the following is a true statement about the graph?
Choose 1 answer:
(A) The graph goes through the point 
(-1,2).
B The graph has a slope of 2 .
(C) The graph goes through the point 
(0,0).
D The graph has a slope of 
(1)/(2).

The equation \newlinex2y=0-x-2y=0 is graphed in the \newlinexyxy-plane. Which of the following is a true statement about the graph?\newlineChoose 11 answer:\newline(A) The graph goes through the point \newline(1,2)(-1,2).\newline(B) The graph has a slope of 22.\newline(C) The graph goes through the point \newline(0,0)(0,0).\newline(D) The graph has a slope of \newline12\frac{1}{2}.

Full solution

Q. The equation \newlinex2y=0-x-2y=0 is graphed in the \newlinexyxy-plane. Which of the following is a true statement about the graph?\newlineChoose 11 answer:\newline(A) The graph goes through the point \newline(1,2)(-1,2).\newline(B) The graph has a slope of 22.\newline(C) The graph goes through the point \newline(0,0)(0,0).\newline(D) The graph has a slope of \newline12\frac{1}{2}.
  1. Rewrite Equation: Rewrite the equation in slope-intercept form to find the slope and y-intercept.\newlineThe equation given is x2y=0-x - 2y = 0. To rewrite it in slope-intercept form (y=mx+b)(y = mx + b), we need to solve for yy.\newlineAdd xx to both sides to get 2y=x-2y = x.\newlineNow divide both sides by 2-2 to isolate yy: y=(12)xy = (-\frac{1}{2})x.
  2. Analyze Slope-Intercept Form: Analyze the slope-intercept form to determine the slope and y-intercept.\newlineFrom the equation y=(12)xy = (-\frac{1}{2})x, we can see that the slope (mm) is 12-\frac{1}{2} and the y-intercept (bb) is 00, which means the graph goes through the origin (0,0)(0,0).
  3. Check Given Points: Check the given points and slopes against the slope-intercept form.\newline(A) The graph goes through the point (1,2)(-1,2). To check this, substitute x=1x = -1 and y=2y = 2 into the equation y=(1/2)xy = (-1/2)x. We get 2=(1/2)(1)=1/22 = (-1/2)(-1) = 1/2, which is not true. So, option (A) is incorrect.\newline(B) The graph has a slope of 22. This is not true because we found the slope to be 1/2-1/2. So, option (B) is incorrect.\newline(C) The graph goes through the point (0,0)(0,0). This is true because the y-intercept is 00, which means the graph goes through the origin. So, option (C) is correct.\newline(D) The graph has a slope of (1)/(2)(1)/(2). This is not true because we found the slope to be 1/2-1/2, not x=1x = -111. So, option (D) is incorrect.

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