The equation of a parabola is y=x2+8x+26. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2+8x+26. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete the Square:Complete the square to rewrite the equation in vertex form.We have the equation y=x2+8x+26. To complete the square, we need to find a number that, when added and subtracted to the equation, forms a perfect square trinomial with x2+8x. This number is (8/2)2=42=16. We add and subtract 16 within the equation.y=x2+8x+16+26−16
Rewrite and Simplify: Rewrite the equation with the perfect square trinomial and simplify.Now we have y=(x2+8x+16)+26−16. The expression in the parentheses is a perfect square trinomial and can be written as (x+4)2. Simplifying the constants gives us:y=(x+4)2+10
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