The equation of a parabola is y=x2+8x+16. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2+8x+16. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete the Square:Complete the square to rewrite the given equation in vertex form. The given equation is y=x2+8x+16. To complete the square, we need to find a value that makes x2+8x a perfect square trinomial. The value to add and subtract is (8/2)2=42=16. However, since 16 is already present in the equation, we do not need to add or subtract anything further.
Rewrite by Factoring: Rewrite the equation by factoring the perfect square trinomial.The equation y=x2+8x+16 can be rewritten as y=(x+4)2 because x2+8x+16 is already a perfect square trinomial equivalent to (x+4)2.
Final Equation in Vertex Form: Write the final equation in vertex form.The equation in vertex form is y=(x+4)2. This is because the equation y=x2+8x+16 is equivalent to y=(x+4)2, which is already in vertex form with a vertex at (−4,0).
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