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The equation of a parabola is y=x2+8x+11y = x^2 + 8x + 11. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x2+8x+11y = x^2 + 8x + 11. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Understanding vertex form: Understand the vertex form of a parabola.\newlineThe vertex form of a parabola is given by y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Completing the square: Complete the square to transform the given equation into vertex form.\newlineWe have y=x2+8x+11y = x^2 + 8x + 11. To complete the square, we need to add and subtract (82)2\left(\frac{8}{2}\right)^2, which is 1616, inside the x terms.\newliney=x2+8x+1616+11y = x^2 + 8x + 16 - 16 + 11
  3. Factoring and simplifying: Factor the perfect square trinomial and simplify the constant terms.\newliney = (x2+8x+16)16+11(x^2 + 8x + 16) - 16 + 11\newliney = (x+4)25(x + 4)^2 - 5

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