The equation of a parabola is y=x2+6x+6. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2+6x+6. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify vertex form: Identify the vertex form of a parabola.The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete square:Complete the square to transform the given equation into vertex form.We have the equation y=x2+6x+6. To complete the square, we need to find the value that makes x2+6x a perfect square trinomial. This value is (26)2=32=9. We will add and subtract 9 to the equation.
Add and subtract: Add and subtract the value found in Step 2 to the equation.y=x2+6x+9−9+6Now, we can rewrite the equation as:y=(x2+6x+9)−3
Factor and simplify: Factor the perfect square trinomial and simplify the equation.The perfect square trinomial x2+6x+9 can be factored as (x+3)2. So, the equation becomes:y=(x+3)2−3
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