The equation of a parabola is y=x2+6x+2. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2+6x+2. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify vertex form: Identify the vertex form of a parabola.The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete the square:Complete the square to transform the given equation into vertex form.We start with the equation y=x2+6x+2. To complete the square, we need to find the value that makes x2+6x into a perfect square trinomial. This value is (26)2=9. We will add and subtract 9 to the equation.
Add and subtract: Add and subtract 9 to the equation.y=x2+6x+9−9+2Now, we can rewrite the equation by grouping the perfect square trinomial and combining the constants.
Rewrite with perfect square: Rewrite the equation with the perfect square trinomial and combine constants.y=(x2+6x+9)−7The perfect square trinomial is (x+3)2, so we can rewrite the equation as:y=(x+3)2−7
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