Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The equation of a parabola is y=x2+6x+12y = x^2 + 6x + 12. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

Full solution

Q. The equation of a parabola is y=x2+6x+12y = x^2 + 6x + 12. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete the Square: Complete the square to transform the given equation into vertex form.\newlineThe given equation is y=x2+6x+12y = x^2 + 6x + 12. To complete the square, we need to find the value that makes x2+6xx^2 + 6x into a perfect square trinomial. We do this by taking half of the coefficient of xx, which is 62=3\frac{6}{2} = 3, and squaring it to get 99. We then add and subtract this value inside the equation.\newliney=x2+6x+99+12y = x^2 + 6x + 9 - 9 + 12
  3. Rewrite and Simplify: Rewrite the equation with the perfect square trinomial and simplify.\newlineNow we have y=(x2+6x+9)9+12y = (x^2 + 6x + 9) - 9 + 12, which simplifies to y=(x+3)2+3y = (x + 3)^2 + 3.

More problems from Write a quadratic function in vertex form