The equation of a parabola is y=x2+6x+12. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2+6x+12. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete the Square:Complete the square to transform the given equation into vertex form.The given equation is y=x2+6x+12. To complete the square, we need to find the value that makes x2+6x into a perfect square trinomial. We do this by taking half of the coefficient of x, which is 26=3, and squaring it to get 9. We then add and subtract this value inside the equation.y=x2+6x+9−9+12
Rewrite and Simplify: Rewrite the equation with the perfect square trinomial and simplify.Now we have y=(x2+6x+9)−9+12, which simplifies to y=(x+3)2+3.
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