Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The equation of a parabola is y=x2+4x+7y = x^2 + 4x + 7. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

Full solution

Q. The equation of a parabola is y=x2+4x+7y = x^2 + 4x + 7. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete Square: Complete the square to transform the given equation into vertex form.\newlineWe have the equation y=x2+4x+7y = x^2 + 4x + 7. To complete the square, we need to find the value that makes x2+4xx^2 + 4x a perfect square trinomial. This value is (4/2)2=22=4(4/2)^2 = 2^2 = 4. We will add and subtract this value inside the equation.
  3. Add/Subtract Value: Add and subtract the value found in Step 22 to the equation.\newliney=x2+4x+7y = x^2 + 4x + 7\newliney=x2+4x+44+7y = x^2 + 4x + 4 - 4 + 7\newlineWe added and subtracted 44 to complete the square without changing the equation's value.
  4. Rewrite Equation: Rewrite the equation grouping the perfect square trinomial and combining the constants.\newliney=(x2+4x+4)4+7y = (x^2 + 4x + 4) - 4 + 7\newliney=(x+2)2+3y = (x + 2)^2 + 3\newlineNow the equation is in vertex form, where (x+2)2(x + 2)^2 is the perfect square trinomial and 33 is the combined constant.

More problems from Write a quadratic function in vertex form