The equation of a parabola is y=x2−4x+7. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2−4x+7. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify vertex form: Identify the vertex form of a parabola.The vertex form of a parabola is given by the equation y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete the square:Complete the square to rewrite the given equation in vertex form.We have the equation y=x2−4x+7. To complete the square, we need to find the value that makes x2−4x a perfect square trinomial. We do this by taking half of the coefficient of x, squaring it, and adding it to and subtracting it from the equation.Half of −4 is −2, and (−2)2=4. So we add and subtract 4 to the equation.
Add squared number: Add and subtract the squared number to the equation.y=x2−4x+4+7−4Now we have added 4 and subtracted 4, which keeps the equation balanced.
Group and combine: Group the perfect square trinomial and combine the constants.y=(x2−4x+4)+7−4y=(x−2)2+3Now we have the equation in vertex form, where (x−2)2 is the perfect square trinomial and 3 is the combined constant.
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