The equation of a parabola is y=x2−4x−6. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2−4x−6. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify vertex form: Identify the vertex form of a parabola.The vertex form of a parabola is given by the equation y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete square:Complete the square to rewrite the given equation in vertex form.We start with the given equation y=x2−4x−6. To complete the square, we need to find a number that, when added and subtracted to the equation, forms a perfect square trinomial with x2−4x. This number is (24)2=4. We add and subtract 4 inside the equation.y=x2−4x+4−4−6
Rewrite equation: Rewrite the equation to show the perfect square trinomial.Now we group the perfect square trinomial and combine the constants:y=(x2−4x+4)−4−6y=(x−2)2−10
Verify form: Verify the vertex form and check for any mathematical errors.The equation is now in vertex form, y=a(x−h)2+k, where a=1, h=2, and k=−10. There are no mathematical errors in the steps taken to complete the square and rewrite the equation.
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