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The equation of a parabola is y=x24x6y = x^2 - 4x - 6. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x24x6y = x^2 - 4x - 6. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify vertex form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is given by the equation y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete square: Complete the square to rewrite the given equation in vertex form.\newlineWe start with the given equation y=x24x6y = x^2 - 4x - 6. To complete the square, we need to find a number that, when added and subtracted to the equation, forms a perfect square trinomial with x24xx^2 - 4x. This number is (42)2=4(\frac{4}{2})^2 = 4. We add and subtract 44 inside the equation.\newliney=x24x+446y = x^2 - 4x + 4 - 4 - 6
  3. Rewrite equation: Rewrite the equation to show the perfect square trinomial.\newlineNow we group the perfect square trinomial and combine the constants:\newliney=(x24x+4)46y = (x^2 - 4x + 4) - 4 - 6\newliney=(x2)210y = (x - 2)^2 - 10
  4. Verify form: Verify the vertex form and check for any mathematical errors.\newlineThe equation is now in vertex form, y=a(xh)2+ky = a(x - h)^2 + k, where a=1a = 1, h=2h = 2, and k=10k = -10. There are no mathematical errors in the steps taken to complete the square and rewrite the equation.

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