The equation of a parabola is y=x2−4x−2. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2−4x−2. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete Square Transformation:Complete the square to transform the given equation into vertex form.Start with the given equation: y=x2−4x−2.To complete the square, we need to find a value that, when added and subtracted to the equation, forms a perfect square trinomial with the x-terms.The value to add and subtract is (4/2)2=22=4.Add and subtract 4 within the equation: y=x2−4x+4−4−2.
Rewrite Equation with Trinomial: Rewrite the equation with the perfect square trinomial and the constants grouped together.The equation now looks like this: y=(x2−4x+4)−4−2.Factor the perfect square trinomial: y=(x−2)2−4−2.Combine the constants: y=(x−2)2−6.
Final Equation in Vertex Form: Write the final equation in vertex form.The equation in vertex form is y=(x−2)2−6.
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