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The equation of a parabola is y=x24x2y = x^2 - 4x - 2. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x24x2y = x^2 - 4x - 2. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete Square Transformation: Complete the square to transform the given equation into vertex form.\newlineStart with the given equation: y=x24x2y = x^2 - 4x - 2.\newlineTo complete the square, we need to find a value that, when added and subtracted to the equation, forms a perfect square trinomial with the xx-terms.\newlineThe value to add and subtract is (4/2)2=22=4(4/2)^2 = 2^2 = 4.\newlineAdd and subtract 44 within the equation: y=x24x+442y = x^2 - 4x + 4 - 4 - 2.
  3. Rewrite Equation with Trinomial: Rewrite the equation with the perfect square trinomial and the constants grouped together.\newlineThe equation now looks like this: y=(x24x+4)42y = (x^2 - 4x + 4) - 4 - 2.\newlineFactor the perfect square trinomial: y=(x2)242y = (x - 2)^2 - 4 - 2.\newlineCombine the constants: y=(x2)26y = (x - 2)^2 - 6.
  4. Final Equation in Vertex Form: Write the final equation in vertex form.\newlineThe equation in vertex form is y=(x2)26y = (x - 2)^2 - 6.

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