The equation of a parabola is y = x^2 - 4x + 2. Write the equation in vertex form. Write any numbers as integers or simplified proper or improper fractions. ______

Identify vertex form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y = a(x - h)^2 + k, where (h, k) is the vertex of the parabola.Complete the square: Complete the square to transform the given equation into vertex form. We have the equation y = x^2 - 4x + 2. To complete the square, we need to find the value that makes x^2 - 4x a perfect square trinomial. We do this by taking half of the coefficient of x, squaring it, and adding it to and subtracting it from the equation. Half of the coefficient of x is -4/2 = -2. Squaring this gives us (-2)^2 = 4. We add and subtract 4 to the equation.Add squared term: Add and subtract the squared term to the equation. y = x^2 - 4x + 4 - 4 + 2 Now, we can rewrite the equation by grouping the perfect square trinomial and combining the constants.Rewrite in vertex form: Rewrite the equation in vertex form. y = (x^2 - 4x + 4) - 4 + 2 y = (x - 2)^2 - 2 We have now written the equation in vertex form, where (x - 2)^2 is the perfect square trinomial and -2 is the combination of the constants.

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The equation of a parabola is $y = x^2 - 4x + 2$ . Write the equation in vertex form. $\newline$ Write any numbers as integers or simplified proper or improper fractions. $\newline$ ______

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Algebra 1

Write a quadratic function in vertex form

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Q. The equation of a parabola is

y = x^2 - 4x + 2

. Write the equation in vertex form.

\newline

Write any numbers as integers or simplified proper or improper fractions.

\newline

______

Identify vertex form: Identify the vertex form of a parabola. $\newline$ The vertex form of a parabola is given by $y = a(x - h)^2 + k$ , where $(h, k)$ is the vertex of the parabola.
Complete the square: Complete the square to transform the given equation into vertex form. $\newline$ We have the equation $y = x^2 - 4x + 2$ . To complete the square, we need to find the value that makes $x^2 - 4x$ a perfect square trinomial. We do this by taking half of the coefficient of $x$ , squaring it, and adding it to and subtracting it from the equation. $\newline$ Half of the coefficient of $x$ is $-4/2 = -2$ . Squaring this gives us $(-2)^2 = 4$ . We add and subtract $4$ to the equation.
Add squared term: Add and subtract the squared term to the equation. $\newline$ $y = x^2 - 4x + 4 - 4 + 2$ $\newline$ Now, we can rewrite the equation by grouping the perfect square trinomial and combining the constants.
Rewrite in vertex form: Rewrite the equation in vertex form. $\newline$ $y = (x^2 - 4x + 4) - 4 + 2$ $\newline$ $y = (x - 2)^2 - 2$ $\newline$ We have now written the equation in vertex form, where $(x - 2)^2$ is the perfect square trinomial and $-2$ is the combination of the constants.