The equation of a parabola is y=x2+4x+14. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2+4x+14. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify vertex form: Identify the vertex form of a parabola.The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete square:Complete the square to transform the given equation into vertex form.We have the equation y=x2+4x+14. To complete the square, we need to find the value that makes x2+4x a perfect square trinomial. This value is (4/2)2=22=4. We will add and subtract this value inside the equation.
Add and subtract: Add and subtract the value found in Step 2 to the equation.y=x2+4x+14y=x2+4x+4−4+14We added and subtracted 4 to complete the square, and we have not changed the equation because adding and subtracting the same number is equivalent to adding zero.
Rewrite equation: Rewrite the equation by grouping the perfect square trinomial and combining the constants.y=(x2+4x+4)−4+14y=(x+2)2+10Now the equation is in vertex form, where (x+2)2 is the perfect square trinomial and 10 is the combined constant.
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