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The equation of a parabola is y=x2+4x−1y = x^2 + 4x - 1. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x2+4x−1y = x^2 + 4x - 1. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Complete the square: Complete the square by finding the value to add and subtract. Use (b2)2(\frac{b}{2})^2 where bb is the coefficient of xx.(42)2=22=4\left(\frac{4}{2}\right)^2 = 2^2 = 4. Add and subtract 44 to the equation.y=x2+4x+4−4−1y = x^2 + 4x + 4 - 4 - 1
  2. Rewrite equation: Rewrite the equation grouping the perfect square trinomial and combining the constants.\newliney=(x2+4x+4)−4−1y = (x^2 + 4x + 4) - 4 - 1\newliney=(x+2)2−5y = (x + 2)^2 - 5

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