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The equation of a parabola is y=x2+2x9y = x^2 + 2x - 9. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x2+2x9y = x^2 + 2x - 9. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify Vertex Form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete Square: Complete the square to rewrite the equation y=x2+2x9y = x^2 + 2x - 9 in vertex form.\newlineFirst, we need to complete the square for the xx-terms. To do this, we take the coefficient of xx, which is 22, divide it by 22, and square it. This gives us (2/2)2=12=1(2/2)^2 = 1^2 = 1. We will add and subtract this value inside the equation.
  3. Add/Subtract Value: Add and subtract the value found in Step 22 inside the equation.\newliney=x2+2x+119y = x^2 + 2x + 1 - 1 - 9\newlineNow, we have added 11 and subtracted 11, which keeps the equation balanced.
  4. Group Perfect Square: Group the perfect square trinomial and combine the constants.\newliney=(x2+2x+1)19y = (x^2 + 2x + 1) - 1 - 9\newliney=(x+1)210y = (x + 1)^2 - 10\newlineWe have now written the equation in vertex form, where (x+1)2(x + 1)^2 is the perfect square trinomial and 10-10 is the combination of the constants.

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